Quantcast
Channel: CodeSection,代码区,Python开发技术文章_教程 - CodeSec
Viewing all articles
Browse latest Browse all 9596

python中快速进行多个字符替换的方法小结

$
0
0

先给出结论:

要替换的字符数量不多时,可以直接链式replace()方法进行替换,效率非常高;

如果要替换的字符数量较多,则推荐在 for 循环中调用 replace() 进行替换。

可行的方法:

1. 链式replace()

string.replace().replace()

     1.x 在for循环中调用replace() 「在要替换的字符较多时」

2. 使用string.maketrans

3. 先 re.compile 然后 re.sub

……

def a(text):
chars = ""
for c in chars:
text = text.replace(c, "\\" + c)
def b(text):
for ch in ['&','#']:
if ch in text:
text = text.replace(ch,"\\"+ch)
import re
def c(text):
rx = re.compile('([])')
text = rx.sub(r'\\\1', text)
RX = re.compile('([])')
def d(text):
text = RX.sub(r'\\\1', text)
def mk_esc(esc_chars):
return lambda s: ''.join(['\\' + c if c in esc_chars else c for c in s])
esc = mk_esc('')
def e(text):
esc(text)
def f(text):
text = text.replace('&', '\&').replace('#', '\#')
def g(text):
replacements = {"&": "\&", "#": "\#"}
text = "".join([replacements.get(c, c) for c in text])
def h(text):
text = text.replace('&', r'\&')
text = text.replace('#', r'\#')
def i(text):
text = text.replace('&', r'\&').replace('#', r'\#')

参考链接:

http://stackoverflow.com/questions/3411771/multiple-character-replace-with-python
http://stackoverflow.com/questions/6116978/python-replace-multiple-strings
http://stackoverflow.com/questions/8687018/python-string-replace-two-things-at-once

http://stackoverflow.com/questions/28775049/most-efficient-way-to-replace-multiple-characters-in-a-string

总结

以上就是这篇文章的全部内容了,希望本文的内容对大家学习或者使用python能有所帮在,如果有疑问大家可以留言交流。


Viewing all articles
Browse latest Browse all 9596

Trending Articles